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# RS Aggarwal Class 10 Chapter 17 Solutions (Volume and Surface Area of Solids)

RS Aggarwal Maths Solutions For Class 10 Chapter 17 ‘Volume and Surface Area of Solids’ can certainly be a great help to you if you are willing to score well in your CBSE Class 10 board exams. In this chapter of RS Aggarwal Class 10 Maths Solutions, you will learn to find the surface area and volume of basic three-dimensional solids such as cones, cuboid, sphere, hemisphere etc. You will also learn how to calculate the surface area and volume in case of a combination of solids and hollow solids.

Chapter 17 of RS Aggarwal Class 10 book contains 4 exercises and 127 questions with 80 multiple-choice questions that will give you a thorough understanding of the chapter. This chapter can be extremely helpful for you to practice extra questions related to surface areas and volume of solids. The chapter also includes questions where one solid is recast into another solid for instance, a cuboid is melted to form a number of cubes and you have to hence calculate the volume or surface area of the new solid formed.

Instasolv’s RS Aggarwal Maths Solutions for Chapter 17 can be an ultimate guide for you with easy and detailed explanations of all the exercise questions of the chapter. These solutions are made by our subject matter experts after a thorough review of each concept involved with the chapter. You can easily refer to them while preparing for CBSE exams.

## Important Topics of RS Aggarwal Maths Solutions For Class 10 Chapter 17: Volume and Surface Area of Solids

• Surface Area of Cuboid: A cuboid has six rectangular faces with the dimensions l, b, h respectively as given in the figure.

Total Surface Area of Cuboid =  2(l×b)+2(b×h)+2(l×h)=2(lb+bh+lh)

Lateral Surface Area = sum of the areas of the lateral faces =  area of face AEHD + area of face BFGC + area of face ABFE + area of face DHGC

• Surface Area of Cube: For a cube, the three dimensions i.e. length, breadth, and height should be the same.

Total Surface Area of Cube = 6 x (length2)

Lateral Surface Area of Cube = 4 x  (length2)

• Surface Area of Cylinder: When a rectangle is folded along its length, it gains a shape of a cylinder.

Curved Surface Area (CSA) of Cylinder = 2π r x h

❖   Total Surface Area of Cylinder =  2 x area of circle of cylinder  + CSA of cylinder

=   2 x π ( square of radius)  +  2π r x h

= 2 π r (r + h)

• Surface Area of Right Circular Cone: For a right circular cone with dimensions – slant height l,  base radius r, and height h respectively.

Curved Surface Area (CSA) of Cone =  π r l

❖ Total Surface Area of Cone = CSA of right circular cone + area of base of cone

= π r l +  π r2

= π r ( l + r)

• Surface Area of Sphere: Let us consider a sphere having radius ‘r’.

Total Surface Area of Sphere =   4 π r2

•       Volume of Cuboid = base area x height  = lbh
•       Volume of Cube = (Length)2
•       Volume of Cylinder π(r2)h
•       Volume of  Right Circular Cone =  ⅓ [π(r2)x h
•       Volume of Sphere = (4/3)πr3

### Exercise Discussion  of RS Aggarwal Class 10 Maths Solutions for Chapter 17: Volume and Surface Area of Solids

Exercise 17A

This exercise has 32 questions based on the concepts of finding the surface area of the cylinder, cuboid, cone, hemisphere, and other solid shapes. In some questions, you are given the ratio of the volumes and radii of two cones and you have to find out the ratio of their heights.

Exercise 17B

It has 34 problems. These questions are tough compared to the last exercise. Questions are generally using the concepts of shape conversion hemispherical shells, spherical shells, cones, etc.

Exercise 17C

This exercise contains 21 questions that will brush your knowledge of the frustum of a cone. You will learn to find its area, volume, the cost involved in painting, applying a metallic sheet on frustum of various dimensions.

Exercise 17D

It has 40 questions. Some of them are based on the ratio of areas and volumes of solids whereas there are some questions based on the recasting of one solid into another.

### Benefits of RS Aggarwal Maths Solutions For Class 10 Chapter 17: Volume and Surface Area of Solids by Instasolv

• Using Instasolv’s RS Aggarwal Solutions for Chapter 17 of Class 10 is the right source of material for you as these solutions help you to revise the concepts easily.
• When you are done with your school textbook, this is a must supplementary book for practice purposes, as it offers easy to understand, simple and clear-cut solutions of the problems related to surface area and volume of solids.
• You know maths problem-solving needs a lot of practice. Instasolv understands the situation, helps you in solving maths complex problems at your own pace.
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