# RS Aggarwal Class 9 Chapter 15 Solutions (Volume and Surface Area of Solids)

RS Aggarwal Solution for Class 9 Maths Chapter 15 –Volume and Surface Area of Solids is the best reference material for you to clear your doubts. In this chapter of RS Aggarwal Class 9 Maths Solutions, there are a total of 110 problems divided into 5 exercises. Solutions are well structured to improve your concept-based knowledge. You shall learn to solve different problems by applying concerned formulas to find the volume, total surface area and radii of a cube, cuboids, cylinders, right circular cone, sphere, spherical shell, and hemisphere.

Our subject matter experts have prepared the solution in a precise way, with a concept-based approach which is crucial from the exam perspective. Our RS Aggarwal Solutions are well structured and improve your knowledge-base. You can refer to the RS Aggarwal Solution for Class 9 to revise chapter 15 while preparing for the exams.

RS Aggarwal Solution for Class 9 Maths Chapter 15 –Volume and Surface Area of Solids by instasolv experts accurately formulate practice answers based on your understanding ability. The best part is that you can access these solutions for free at the comfort of your home.

## Important Topics for RS Aggarwal Solution for Class 9 Maths Chapter 15 –Volume and Surface Area of Solids

Given below some highlighted facts and formulas used in this chapter:

- Three measures of the significant tendency of ungrouped facts are: (i) mean, (ii) median and (iii) mode.
- Total surface area (TSA) of a cuboid is equal to 2[lb + bh + lh].
- The total surface area of a cube equals 6(side)
^{2}. - The lateral surface area of a cuboid is equal to the Area of walls of room = 2(l + b) × h.
- The lateral surface area of a cube equals to 4a
^{2} - The curved surface area of a cylinder is equal to 2πrh
- The total surface area of a cylinder is equal to 2πr(r + h)
- The curved surface area of a cone is equal to πrl
- The total surface area of a cone is equal to πr(r + l)
- The surface area of a sphere is equal to 4πr
^{2} - The curved surface area of a hemisphere is equal to = 2πr
^{2} - The total surface area of a hemisphere is equal to 3πr
^{2} - The volume of a cuboid is equal to l × b × h
- The volume of a cube equals to = (side)
^{2} - The volume of a cylinder is equal to πr
^{2}h

**SOLIDS AND THEIR SURFACE AREAS**

• When bodies occupy an area are known as solids, inclusive of a cuboid, a cube, a cylinder, a cone, a sphere, etc.

• Solids have either plane or curved surfaces.

**SURFACE AREA OF A CUBOID AND A CUBE**

- The outer surface of a cuboid is made up of six rectangles. If we take the length of the cuboid as l, breadth as b and the height as h, then
- Surface area of a cuboid = 2[lb + bh + hl]
- Let us recall that a cuboid whose length, breadth and height are equal is called a cube. Let each edge of the cube be a’, then
- The surface area of a cube equals to 6a
^{2}

**SURFACE AREA OF A CUBOID AND A CUBE**

- The outer surface of a cuboid is made of six rectangles. If we take the period total length of the cuboid as “l”, breadth as “b” and the height as “h”, then,

as per the Surface area of a cuboid equals “ 2[lb + bh + hl]”. - Let us recall that a cuboid whose length, breadth and height are identical is called a cube. Let each edge of the dice be “a”, then the surface region of a cube equals 6a
^{2}.

** Note**:

- Sometimes when a cuboid does not have bottom and top faces it is called the lateral surface area (LSA).
- The lateral surface area of a cuboid is equal to “2(l + b)h”.
- The lateral surface area of a cube equals 4a
^{2}. - The surface area of a cuboid or a cube is always said to be their total surface area.

**Exercise Discussion of Important Topics RS Aggarwal Solution for Class 9 Maths Chapter 15**

- The first exercise 15A of Chapter 15 essentially contains 28 questions that will ask you to find volumes of lateral surface area and total surface area of cuboids and cubes by using given dimensions.
- The second exercise 15 B of Chapter 15 gives reason type problems having 33 questions that will ask you to justify your answers that are mainly based on different formulas of curved surface area, total surface area and volume of the cylinder. These problems are diagrammatically solved for your easy understanding.
- Math Chapter 15 Exercise 15C contains 21 questions based on several problems with solutions that are marked fetching in nature. These questions are related to the formulas of curved surface area, total surface area and volume of a right circular cone. These RS Aggarwal issues with solutions can be observed for final examinations.
- Maths Chapter 15 Exercise 15D contains 28 questions based on several problems with solutions that are marked fetching in nature.
- This exercise will help you to understand the use of different formulas for volume and surface area of a sphere, spherical shell and hemisphere in different questions that are asked in this exercise.
- Instasolv will help you in fixing and clarifying your doubts about the questions on this Exercise. Though these questions may appear easy, they need complete preparation.

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Instasolv’s RS Aggarwal Solutions for Class 9 Chapter 15 will help you to promote a deeper understanding of every concept in a very simplified and accurate way.

It is very important to have a clear cut concept of this chapter and the stepwise solutions provided by us will give you that.